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ClosestPrimeNumbersInRange.java
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70 lines (58 loc) · 2.03 KB
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package com.thealgorithms.leetcode;
import java.util.Arrays;
public class ClosestPrimeNumbersInRange {
public int[] closestPrimes(int left, int right) {
// get all primes up to right
boolean[] isPrime = sieveOfEratosthenes(right);
// first two primes in range
int first = -1;
int second = -1;
int minDiff = Integer.MAX_VALUE;
int prev = -1;
for (int i = Math.max(2, left); i <= right; i++) {
if (isPrime[i]) {
if (prev == -1) {
prev = i;
} else {
int diff = i - prev;
if (diff < minDiff) {
minDiff = diff;
first = prev;
second = i;
}
prev = i;
}
}
}
return first == -1 ? new int[]{-1, -1} : new int[]{first, second};
}
public boolean isPrime(int n) {
if (n <= 1) return false;
if (n <= 3) return true;
if (n % 2 == 0 || n % 3 == 0) return false;
// check for prime by testing divisors up to square root of n, can skip even numbers
// and optimize by checking only numbers of form 6k + 1
for (int i = 5; i * i <= n; i+= 6) {
if (n % i == 0 || n % (i + 2) == 0) {
return false;
}
}
return true;
}
// helper method to find prime numbers using sieve of eratosthenes
public static boolean[] sieveOfEratosthenes(int n) {
boolean[] isPrime = new boolean[n+1];
Arrays.fill(isPrime, true);
isPrime[0] = false;
isPrime[1] = false;
for (int i = 2; i * i <= n; i++) {
if (isPrime[i]) {
for (int j = i * i; j <= n; j += i) {
isPrime[j] = false;
}
}
}
return isPrime;
}
}
// https://leetcode.com/problems/closest-prime-numbers-in-range/description/