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0088.Merge_Sorted_Array.py
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71 lines (55 loc) Β· 2.08 KB
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/*
You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively.
Merge nums1 and nums2 into a single array sorted in non-decreasing order.
The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ignored. nums2 has a length of n.
Example 1:
Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Explanation: The arrays we are merging are [1,2,3] and [2,5,6].
The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.
*/
//version:python
class Solution:
def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
"""
Do not return anything, modify nums1 in-place instead.
"""
index = len(nums1) - 1
m -= 1
n -= 1
while m >= 0 and n >= 0:
if nums1[m] > nums2[n]:
nums1[index] = nums1[m]
m -= 1
index -= 1
else:
nums1[index] = nums2[n]
n -= 1
index -= 1
while m >= 0:
nums1[index] = nums1[m]
m -= 1
index -= 1
while n >= 0:
nums1[index] = nums2[n]
n -= 1
index -= 1
class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int index = nums1.length - 1;
int i = m -1, j = n - 1;
while ((i >= 0) && (j >= 0)) {
if (nums2[j] >= nums1[i]) {
nums1[index--] = nums2[j--];
} else {
nums1[index--] = nums1[i--];
}
}
while (i >= 0) {
nums1[index--] = nums1[i--];
}
while (j >= 0) {
nums1[index--] = nums2[j--];
}
}
}