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20 changes: 15 additions & 5 deletions Exercise_1.py
Original file line number Diff line number Diff line change
@@ -1,21 +1,31 @@
#Time Complexity: o(1)
# #Space Complexity:0(n)
class myStack:
#Please read sample.java file before starting.
#Kindly include Time and Space complexity at top of each file
def __init__(self):
self.stack=[]

def isEmpty(self):

return len(self.stack)==0

def push(self, item):
self.stack.append(item)

def pop(self):

if self.isEmpty():
return None
return self.stack.pop()

def peek(self):

if self.isEmpty():
return None
return self.stack[-1]
def size(self):

return len(self.stack)
def show(self):

return self.stack


s = myStack()
s.push('1')
Expand Down
15 changes: 12 additions & 3 deletions Exercise_2.py
Original file line number Diff line number Diff line change
@@ -1,15 +1,24 @@

#Time Complexity: O(1)
#Space Complexity: O(n)
class Node:
def __init__(self, data):
self.data = data
self.next = None

class Stack:
def __init__(self):
self.top = None

def push(self, data):

def pop(self):
new_node=Node(data)
new_node.next=self.top
self.top=new_node
def pop(self):
if self.top is None:
return None
popitem = self.top.data
self.top=self.top.next
return popitem

a_stack = Stack()
while True:
Expand Down
35 changes: 33 additions & 2 deletions Exercise_3.py
Original file line number Diff line number Diff line change
@@ -1,9 +1,14 @@
# Time Complexity : O(n)
# Space Complexity : O(n)

class ListNode:
"""
A node in a singly-linked list.
"""
def __init__(self, data=None, next=None):

self.data = data
self.next = next

class SinglyLinkedList:
def __init__(self):
"""
Expand All @@ -17,16 +22,42 @@ def append(self, data):
Insert a new element at the end of the list.
Takes O(n) time.
"""
new_node = ListNode(data)
if self.head is None:
self.head = new_node
return
current = self.head
while current.next is not None:
current = current.next
current.next = new_node


def find(self, key):
"""
Search for the first element with `data` matching
`key`. Return the element or `None` if not found.
Takes O(n) time.
"""

current = self.head
while current is not None:
if current.data == key:
return current
current = current.next
return None
def remove(self, key):
"""
Remove the first occurrence of `key` in the list.
Takes O(n) time.
"""
if self.head is None:
return
if self.head.data == key:
self.head = self.head.next
return
current = self.head
while current.next is not None:
if current.next.data == key:
current.next = current.next.next
return
current = current.next